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Algebra - Order of Operations Revisited
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Algebra - Order of Operations Revisited

This Math quiz is called 'Algebra - Order of Operations Revisited' and it has been written by teachers to help you if you are studying the subject at middle school. Playing educational quizzes is a fabulous way to learn if you are in the 6th, 7th or 8th grade - aged 11 to 14.

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Can you imagine what it would be like if math was done differently from one country to another? At the very least, it would cause economic chaos. So, although the world is divided into multiple different cultures and languages, mathematicians throughout the world worked together over the centuries to develop a common formula and method to solving all mathematical problems.

1.
Helpful comment
2.
Helpful comment
3.
135 ÷ 15 + (6 x 8) - (84 ÷ 12) + 34 =
311
113
131
31
Working the problem we get the following:<br />
P: 6 x 8 = 48<br />
P: 84 &divide; 12 = 7<br />
E: 3<sup>4</sup> = 3 x 3 = 9 x 3 = 27 x 3 = 81<br />
135 &divide; 15 + (6 x 8) - (84 &divide; 12) + 3<sup>4</sup> = 135 &divide; 15 + 48 - 7 + 81 = <br />
MD: 135 &divide; 15 = 9<br />
AS: 9 + 48 = 57<br />
AS: 57 - 7 = 50<br />
AS: 50 + 81 = 131<br />
<b><u>Solution</u>:</b> 135 &divide; 15 + (6 x 8) - (84 &divide; 12) + 34 = <b><u>131</u></b><br />
Answer (c) is the correct answer
4.
Helpful comment
5.
Helpful comment
6.
21 x 3 + (32 - 11) + 6 x (15 ÷ 5) =
270
102
522
114
Working the problem we get the following:<br />
P: 32 - 11 = 21<br />
P: 15 &divide; 5 = 3<br />
21 x 3 + (32 - 11) + 6 x (15 &divide; 5) = (21 x 3) + 21 + (6 x 3)<br />
P: 21 x 3 = 63<br />
P: 6 x 3 = 18<br />
AS: 63 + 21 + 18 = 102<br />
<b><u>Solution</u>:</b> 21 x 3 + (32 - 11) + 6 x (15 &divide; 5) = <b><u>102</b></u><br />
As you can see, we worked the problem within the parentheses first giving us the sums of “21” and then “3”.  As we have a mixture of mathematical terms, we need to offset these using parentheses.  This is why 21 x 3 becomes (21 x 3) and 6 x 3 (the 3 here as the result of our dividing 15 by 5), we put parenthesis around the (6 x 3).  The addition of 21 comes between the two parentheses.  The original problem was then simplified to read as (21 x 3) + 21 + (6 x 3) =.  This once again gave us parentheses which we need to work first.  Once this was worked we no longer had any multiplication or division so we moved to the addition/subtraction set.  The correct solution for this problem then is Answer (b)
7.
99 - 14 + (41 + 11) + 7 + (65 - 10) - (4 x 3) + 62 =
223
249
119
29
Working the problem we get the following:<br />
P: 41 + 11 = 52<br />
P: 65 - 10 = 55<br />
P: 4 x 3 = 12<br />
E: 6<sup>2</sup> = 6 x 6 = 36<br />
99 - 14 + (41 + 11) + 7 + (65 - 10) - (4 x 3) + 62 = 99 - 14 + 52 + 7 + 55 - 12 + 36 = <br />
AS: 99 - 14 = 85<br />
AS: 85 + 52 + 7 + 55 = 199<br />
AS: 199 - 12 = 187<br />
AS: 187 + 36 = 223<br />
<b><u>Solution</u>:</b> 99 - 14 + (41 + 11) + 7 + (65 - 10) - (4 x 3) + 6<sup>2</sup> = <b><u>223</u></b><br />
Answer (a) is the correct answer
8.
22 + 34 + (4 x 10) - 4 + (9 x 2) =
738
1210
74
110
Working the problem we get the following:<br />
P: 4 x 10 = 40<br />
P: 9 x 2 = 18<br />
22 + 34 + (4 x 10) - 4 + (9 x 2) = 22 + 34 + 40 - 4 + 18 =<br />
AS: 22 + 34 + 40 = 96<br />
AS: 96 - 4 = 92<br />
AS: 92 + 18 = 110<br />
<b><u>Solution</u>:</b> 22 + 34 + (4 x 10) - 4 + (9 x 2) = <b><u>110</u></b><br />
Answer (d) is the correct solution
9.
(6 x 11) + (12 x 11) - (128 ÷ 8) + 3(y + x2) =
182 + 6yx2
182 + 3y + 3x6
179 + y + x2
182 + 3y + 3x2
Working the problem we get the following:<br />
P: 6 x 11 = 66<br />
P: 12 x 11 = 132<br />
P: 128 &divide; 8 = 16<br />
P: <i>y</i> and <i>x</i> are not like terms so they cannot be added together.  However, each is to be multiplied by the “3” outside of their parenthesis making 3(<i>y</i> + <i>x</i><sup>2</sup>) = 3<i>y</i> + 3<i>x</i><sup>2</sup><br />
(6 x 11) + (12 x 11) - (128 &divide; 8) + 3(<i>y</i> + <i>x</i><sup>2</sup>) = 66 + 132 - 16 + 3<i>y</i> + 3<i>x</i><sup>2</sup> =<br />
AS: 66 + 132 = 198<br />
AS: 198 - 16 = 182<br />
Again, as 3<i>y</i> and 3<i>x</i><sup>2</sup> are not like terms, this is as far as we can go with them.<br />
<b><u>Solution</u>:</b> (6 x 11) + (12 x 11) - (128 &divide; 8) + 3(<i>y</i> + <i>x</i><sup>2</sup>) = <b><u>182 + 3<i>y</i> + 3<i>x</i><sup>2</sup></u></b><br />
Answer (d) is the correct answer
10.
54 + 33 + (5 x 17) - 101 + (28 ÷ 7) - 3 + 40 =
675
677
54
57
Working the problem we get the following:<br />
P: 5 x 17 = 85<br />
P: 28 &divide; 7 = 4<br />
E: 5<sup>4</sup> = 5 x 5 = 25 x 5 = 125 x 5 = 625<br />
E: 3<sup>3</sup> = 3 x 3 = 9 x 3 = 27<br />
5<sup>4</sup> + 3<sup>3</sup> + (5 x 17) - 101 + (28 &divide; 7) - 3 + 40 = 625 + 27 + 85 - 101 + 4 - 3 + 40 = <br />
AS: 625 + 27 + 85 = 737<br />
AS: 737 - 101 = 636<br />
AS: 636 + 4 = 640<br />
AS: 640 - 3 = 637<br />
AS: 637 + 40 = 677<br />
<b><u>Solution</u>:</b> 54 + 33 + (5 x 17) - 101 + (28 &divide; 7) - 3 + 40 = <b><u>677</u></b><br />
Answer (b) is the correct answer
Author:  Christine G. Broome

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