Upper & Lower Bounds (H)

The height of a door is stated as 2m. This implies that the number is stated, to the nearest metre. How tall, and how small, COULD the door have been? It could have been as tall as 2.5m (but not including 2.5), as any number in this interval would round down to 2. Similarly, it could have been as small as 1.5m, as anything above this would round to 2m. We could write this as an inequality, 1.5m ≤ door height < 2.5m.

However, if the height is given as 2.00m then it is much more accurate, as it is given to the nearest hundredth of a metre (or nearest cm). The maximum height it could have been is now only 2.005m, or as small as 1.995m. This can be written as 1.995m ≤ door height < 2.005m.

With a bit of practise you should start to see the technique – add and subtract half a unit at the level of accuracy stated.

Calculating with error bounds needs a bit more care and planning, particularly when dividing is involved.