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Analysing Substances - Quantitative
If 9g of aluminium reacts with 35.5g of chlorine, the empirical formula of the compound formed is A1C13

Analysing Substances - Quantitative

Analysing substances forms a major part of GCSE Chemistry. This is the last of three quizzes on the topic and it is all about quantitative analysis. This kind of analysis allows us to identify the amounts of different elements present in compounds.

Analysing substances quantitatively answers the question of 'how much'. It involves carrying out experiments that give you results for use in calculations. The calculations indicate the amouts of each element present in a compound and can be given as a percentage or as a mass. These calculations often involve the use of a quantity called the mole. Many students are put off by this as it is not something that they have come across before the GCSE. It should not be worrying - it is just like using more familiar terms like 'thousand', 'million', 'billion' and so on. It is just a word that is used to represent a large number of particles and it really makes life much easier when carrying out chemical calculations.

1 .
What is the relative formula mass of copper sulfate CuSO4?
160 amu
96 amu
128 amu
144 amu
amu = atomic mass units
2 .
What is the relative formula mass of MgF2?
60 amu
62 amu
43 amu
64 amu

 Mg = 24 amu, F = 19 amu, remember that there are 2 F atoms in the molecule of MgF2

3 .
What % mass of magnesium oxide is magnesium?
60%
40%
30%
70%
First you work out the relative formula mass of magnesium oxide (MgO) then divide the relative atomic mass of magnesium by the relative formula mass and multiply by 100 for the percentage
4 .
What is the % mass of hydrogen in methane CH4?
20%
25%
75%
12.5%
Use the same method as for the previous question
5 .
Calcium reacts with oxygen as shown by this reaction 2Ca + O2 → 2CaO. What mass of oxygen will react with 60g of calcium?
12g
24g
6g
14g
From the equation, you find that they react in a ratio of 2 moles to 1 mole. 60g of calcium is 1.5 moles so you will need 0.75 moles of oxygen molecules
6 .
Sodium hydroxide reacts with chlorine to make bleach as shown by this reaction. 2NaOH + Cl2 → NaOCl + NaCl + H2O. If we have a solution containing 100g of sodium hydroxide, how much chlorine gas should we pass through the solution to make bleach?
28.65g
82.45g
88.75g
86.57g

Ratio of sodium hydroxide to chlorine is 2 moles to1 mole

7 .
If 9g of aluminium reacts with 35.5g of chlorine, what is the empirical formula of the compound formed?
AlCl
AlCl2
AlCl3
Al3Cl
Use moles! One third of a mole of aluminium atoms react with 1 mole of chlorine atoms therefore there are three times as many chlorine atoms involved. Remember, the mole is nothing more complicated than a measure of the number of particles in a reaction
8 .
A compound contains 13.5g of calcium, 10.8g of oxygen and 0.675g of hydrogen. What is its empirical formula?
CaOH
CaOH2
CaO2H
Ca(OH)2
It's those moles again ...
9 .
A reaction that could theoretically produce 200g of product only produces 140g. What is its % yield?
70%
14.2%
142%
7%
Divide the actual yield by the theoretical yield and multiply by 100
10 .
Ammonium nitrate NH4NO3 is used as a fertiliser. What is the % mass of nitrogen in it?
21%
37%
17.5%
35%
Divide the total relative atomic mass of the nitrogen in the formula by the relative formula mass and multiply by 100
You can find more about this topic by visiting BBC Bitesize - Analysing substances

Author:  Kate Gardiner

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